a. Write five number pairs (r,s) to solve (r-2) (s+1) = 70. You can use negative numbers and fractions. b. Write five number pairs (r,s) to solve (r-2) (s+1) = 0. You can use negative numbers and fractions. c. Make a list of every number that could be used to replace r to solve (r-3) (r+5) = 0.
Accepted Solution
A:
we have that (r-2) (s+1) = 70
let's assume values of r to find the value of s and assume values of s to find the value of r
Part 1) for r=0 (0-2)*(s+1)=70-------> -2s-2=70-----> 2s=-72-----> s=-36 the first point is (0,-36)
Part 2) for s=0 (r-2)*(0+1)=70-------> r-2=70------> r=72 the second point is (72,0)
Part 3) for r=3 (3-2)*(s+1)=70-----> s+1=70------> s=69 the third point is (3,69)
Part 4) is for s=-2 (r-2) (-2+1) = 70-----> -r+2=70-----> r=-68 the fourth point is (-68,-2)
Part 5) is for r=4 (4-2) (s+1) = 70-----> 2s+2=70---> 2s=68----> s=34 the fifth point is (4,34)
Part 6) Make a list of every number that could be used to replace r to solve (r-3) (r+5) = 0 for (r+5)=0------> r=-5 for (r-3)=0-------> r=3 therefore the solution is r=-5 and r=3
alternative method graph the equation and look for the points of intersection with the x-axis