Answer: (x, y, z) = (1-z, z, z) . . . . . . . an infinite number of solutionsStep-by-step explanation:Use the first equation to substitute for x in the remaining two equations. (-5y +4z +1) -2y +3z = 1 . . . . substitute for x in the second equation -7y +7z = 0 . . . . . . . . . . . . . . simplify, subtract 1 y = z . . . . . . . . . . . . . . . . . . . . divide by -7; add z__ 2(-5y +4z +1) +3y -z = 2 . . . . substitute for x in the third equation -7y +7z = 0 . . . . . . . . . . . . . . subtract 2; collect terms y = z . . . . . . . . . . . . . . . . . . . . divide by -7; add zThis is a dependent set of equations, so has an infinite number of solutions. Effectively, they are ... x = 1 -z y = z z is a "free variable"