USE DISTANECE= RATE * TIME 1- Anjali traveled to teh recycling plant and back. The trip there took 5.8 hrs and the trip back took 5.1 hrs. She averaged 7 mph faster on the return trip than the outbound trip. What was Anjali's average speed on the outbound trip?2- A fishing boat left Hawaii traveling west 0.5 hrs before a cruise ship. the cruise ship traveled in the opposite direction going 12.5km/h faster than the fishing boat for 11 hrs after which the time the ships were 322 km apart. What was te fishing boat's speed.
Accepted Solution
A:
a] D=R×t d=5.8r d2=5.1(r+7) 0.7r=35.7 r=51 mi/hr thus the average speed on the outbound trip would be: 51+7=58 mi/hr
b] let speed of fishing boat=x km/h speed of cruise ship=(x+12.5) km/h distance traveled by fishing boat=11.5×x=11.5x km distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km Total distance covered by the ships: 11.5x+11x+137.5=322 22.5x=322-137.5 22.5x=184.5 thus x=184.5/22.5 x=8.2 km/h The speed of fishing boat is 8.2 km/hr